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8x^2-30x+54=2x^2+30x
We move all terms to the left:
8x^2-30x+54-(2x^2+30x)=0
We get rid of parentheses
8x^2-2x^2-30x-30x+54=0
We add all the numbers together, and all the variables
6x^2-60x+54=0
a = 6; b = -60; c = +54;
Δ = b2-4ac
Δ = -602-4·6·54
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-48}{2*6}=\frac{12}{12} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+48}{2*6}=\frac{108}{12} =9 $
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